I will choose the bottom node as the reference node and assign
node voltages V_{A}, V_{B},
and V_{C} to the remaining nodes.

Define v_{}D (used to define the dependent source)
in terms of node voltages.

v

_{}D = V_{A}- V_{B}

Node A forms a supernode with the reference node due to the 50 V source (shown with a dotted outline):

V

_{A}= 50

Nodes B and C also form a supernode due to the dependent voltage source (shown with a dotted outline):

V

_{B}- V_{C}= v_{}D / 5 = (V_{A}- V_{B}) / 5V

_{B}- V_{C}= (50 - V_{B}) / 51.2 V

_{B}- V_{C}= 10 (Eq. 1)

KCL at supernode B-C:

Simplify and collect terms (LCD = 390)

39 V

_{A}- 39 V_{B}- 13 V_{B}- 10 V_{C}- 5 V_{C}= 039 (50) - 52 V

_{B}- 15 V_{C}= 0- 52 V

_{B}- 15 V_{C}= - 1950 (Eq. 2)

Solving Equations 1 and 2 yields:

V_{A} = 50 V

V_{B} = 30 V

V_{C} = 26
V = V_{o}