Example 6.6 (LINDO output)


MAX     6 X1 + 3 X2 + 4 X3
 SUBJECT TO
        2)   X1 + 2 X2 + X3 <=   8
        3)   5 X1 + 4 X2 + 3 X3 <=   25

 
 LP OPTIMUM FOUND AT STEP      2

        OBJECTIVE FUNCTION VALUE

        1)    33.0000000    

  VARIABLE        VALUE          REDUCED COST
        X1          .500000           .000000
        X2          .000000          3.000000
        X3         7.500000           .000000


       ROW   SLACK OR SURPLUS     DUAL PRICES
        2)          .000000          1.000000
        3)          .000000          1.000000

 NO. ITERATIONS=       2